Q: How do you factor 385 into a product of primes?

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The prime 5, 7, and 11 yield the product 385 when multiplied together.

Two.

As a product of its prime factors: 2*61 = 122

Factor tree.

38 = 2 X 19

As a product of its prime factors: 2*2*5*5 = 100

i think it is 10 times 11 but it said it was wrong for me on hegarty maths

As a product of its prime factors in exponents: 2^3 times 5^2 = 200

48 = 2 × 2 × 2 × 2 × 3

Yes, they are relatively prime.

There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.

7 is prime, and 55 is the product of the primes 5 and 11. There are therefore no common factors, so the greatest common factor of 55 and 7 is 1. So, the LCM of 55 and 7 is 55*7=385.

2 x 3 x 5 x 7 = 210

The prime factors of 70 are 2,5 and 7 so their product is 70. This will happen whenever the prime factors occur only once. When we factor 70 into primes, we are asking for those primes who product is equal to 70. However, sometimes we get one or more primes raise to a power in the prime factorization. In this case, the prime raised to a power is no longer a prime so the product of prime factors is less than the number.

5x7

2x2x2x2x2x2

Since 77 is a factor of 385, it is automatically the GCF.

The products of the primes are the composites.

7x7

It can be, if you're comparing primes or relative primes.

95 is the product of two primes, 5 and 19.

The greatest common factor of 12 and 385 is 1.

102 = 2*3*17

As a product of its prime factors: 2*2*2*2*2*2*2*2 = 256 or as 2^8 = 256

35, 55, 77, 385 must be.

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